Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If I = 
tan –1 (e x ) dx, then I equals:
A
– e –x tan –1 (e x ) + log (1 + e 2x ) + CB
B
x – e –x tan –1 e x – 
log (1 + e x ) + C
log (1 + e x ) + C
C
x – e –x tan –1 (e x ) – 
log (1 + e 2x ) + C
log (1 + e 2x ) + C
D
None of these
Text Solution
Verified by ExpertsThe correct answer is:
C
put e x = t to get
I = 
tan –1 (t) dt
= (tan –1 t) 
– 
= – 
tan –1 t + 
= – 
tan –1 t + 
= – 
tan –1 t + λ nt – 
λ n (1+ t 2 ) + C
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